In this section, we are going to find a solution in Ruby for the math problem that asks this: evaluate the sum of all the amicable numbers under 10,000.
So that made perfect sense, right? In case your amicable number knowledge is a little rusty like mine was, let's look at a definition of amicable numbers:
Let d(n) be defined as the sum of proper divisors of n (numbers less than n that could be divided evenly into n). If d(a) = b and d(b) = a, where a ≠b, then a and b are an amicable pair, and both a and b are called amicable numbers.
Still unclear? The following is the full explanation:
Essentially, you take a number, identify all its divisors, and add them together to get a value. Next, take that final sum value, identify its divisors, and add them together. If this second sum value is the same as the original number for...
