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Java Coding Problems

You're reading from   Java Coding Problems Become an expert Java programmer by solving over 250 brand-new, modern, real-world problems

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Product type Paperback
Published in Mar 2024
Publisher Packt
ISBN-13 9781837633944
Length 798 pages
Edition 2nd Edition
Languages
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Author (1):
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Anghel Leonard Anghel Leonard
Author Profile Icon Anghel Leonard
Anghel Leonard
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Table of Contents (16) Chapters Close

Preface 1. Text Blocks, Locales, Numbers, and Math 2. Objects, Immutability, Switch Expressions, and Pattern Matching FREE CHAPTER 3. Working with Date and Time 4. Records and Record Patterns 5. Arrays, Collections, and Data Structures 6. Java I/O: Context-Specific Deserialization Filters 7. Foreign (Function) Memory API 8. Sealed and Hidden Classes 9. Functional Style Programming – Extending APIs 10. Concurrency – Virtual Threads and Structured Concurrency 11. Concurrency ‒ Virtual Threads and Structured Concurrency: Diving Deeper 12. Garbage Collectors and Dynamic CDS Archives 13. Socket API and Simple Web Server 14. Other Books You May Enjoy
15. Index

39. Checking a sub-range in the range from 0 to length

Checking that a given sub-range is in the range from 0 to the given length is a common check in a lot of problems. For instance, let’s consider that we have to write a function responsible for checking if the client can increase the pressure in a water pipe. The client gives us the current average pressure (avgPressure), the maximum pressure (maxPressure), and the amount of extra pressure that should be applied (unitsOfPressure).

But, before we can apply our secret algorithm, we have to check that the inputs are correct. So, we have to ensure that none of the following cases happens:

  • avgPressure is less than 0
  • unitsOfPressure is less than 0
  • maxPressure is less than 0
  • The range [avgPressure, avgPressure + unitsOfPressure) is out of bounds represented by maxPressure

So, in code lines, our function may look as follows:

public static boolean isPressureSupported(
      int avgPressure, int unitsOfPressure, int maxPressure) {
  if(avgPresure < 0 || unitsOfPressure < 0 || maxPressure < 0
    || (avgPresure + unitsOfPressure) > maxPressure) {
    throw new IndexOutOfBoundsException(
           "One or more parameters are out of bounds");
  }
  // the secret algorithm
  return (avgPressure + unitsOfPressure) <
    (maxPressure - maxPressure/4);
}

Writing composite conditions such as ours is prone to accidental mistakes. It is better to rely on the Java API whenever possible. And, for this use case, it is possible! Starting with JDK 9, in java.util.Objects, we have the method checkFromIndexSize(int fromIndex, int size, int length), and starting with JDK 16, we also have a flavor for long arguments, checkFromIndexSize(int fromIndex, int size, int length). If we consider that avgPressure is fromIndex, unitsOfPressure is size, and maxPressure is length, then checkFromIndexSize() performs the arguments validation and throws an IndexOutOfBoundsException if something goes wrong. So, we write the code as follows:

public static boolean isPressureSupported(
      int avgPressure, int unitsOfPressure, int maxPressure) {
  Objects.checkFromIndexSize(
    avgPressure, unitsOfPressure, maxPressure);
  // the secret algorithm
  return (avgPressure + unitsOfPressure) <
   (maxPressure - maxPressure/4);
}

In the code bundle, you can see one more example of using checkFromIndexSize().

Besides checkFromIndexSize(), in java.util.Objects, we can find several other companions that cover common composite conditions such as checkIndex(int index, int length) – JDK 9, checkIndex(long index, long length) – JDK 16, checkFromToIndex(int fromIndex, int toIndex, int length) – JDK 9, and checkFromToIndex(long fromIndex, long toIndex, long length) – JDK 16.

And, by the way, if we switch the context to strings, then JDK 21 provides an overload of the well-known String.indexOf(), capable of searching a character/substring in a given string between a given begin index and end index. The signature is indexOf(String str, int beginIndex, int endIndex) and it returns the index of the first occurrence of str, or -1 if str is not found. Basically, this is a neat version of s.substring(beginIndex, endIndex).indexOf(str) + beginIndex.

You have been reading a chapter from
Java Coding Problems - Second Edition
Published in: Mar 2024
Publisher: Packt
ISBN-13: 9781837633944
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