Lambda expression limitations

There are two aspects of a Lambda expression that we would like to point out and clarify:

• If a Lambda expression uses a local variable created outside it, this local variable has to be final or effectively final (not reassigned in the same context).
• The this keyword in a Lambda expression refers to the enclosing context, not the Lambda expression itself.

As in an anonymous class, the variable created outside and used inside a Lambda expression becomes effectively final and cannot be modified. The following is an example of an error caused by the attempt to change the value of an initialized variable:

int x = 7;

//x = 3; //compilation error

Function<Integer, Integer> multiply = i -> i * x;

The reason for this restriction is that a function can be passed around and executed in different contexts (different threads, for example), and an attempt to synchronize these contexts would defeat the original idea of the stateless...