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Kotlin Standard Library Cookbook

You're reading from   Kotlin Standard Library Cookbook Master the powerful Kotlin standard library through practical code examples

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Product type Paperback
Published in Jul 2018
Publisher Packt
ISBN-13 9781788837668
Length 242 pages
Edition 1st Edition
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Author (1):
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Samuel Urbanowicz Samuel Urbanowicz
Author Profile Icon Samuel Urbanowicz
Samuel Urbanowicz
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Toc

Table of Contents (11) Chapters Close

Preface 1. Ranges, Progressions, and Sequences 2. Expressive Functions and Adjustable Interfaces FREE CHAPTER 3. Shaping Code with Kotlin Functional Programming Features 4. Powerful Data Processing 5. Tasteful Design Patterns Adopting Kotlin Concepts 6. Friendly I/O Operations 7. Making Asynchronous Programming Great Again 8. Best Practices for the Android, JUnit, and JVM UI Frameworks 9. Miscellaneous 10. Other Books You May Enjoy

Traversing through ranges using progression with a custom step value

Besides doing so for the Iterator instances, progressions implementations for integral types, such as the Int, Long, and Char types, also include the step property. The step value specifies the intervals between the subsequent elements of a range. By default, the step value of a progression is equal to 1. In this recipe, we are going to learn how to traverse a range of alphabet characters with a step value equal to 2. In the result, we want to have every second alphabet letter printed to the console.

Getting ready

The Kotlin standard library provides a convenient way of creating progression with a custom step value. We can do so using an extension function for progressions of integral types called step(). We can also benefit from the infix notation and declare a progression with a custom step, as follows:

val progression: IntProgression = 0..1000 step 100

If we were to use progression in the for loop, it would iterate 10 times:

val progression: IntProgression = 0..1000 step 100
for
(i in progression) {
println(i)
}

We could also achieve the same result by iterating with the while loop, as follows:

var i = 0
while (i <= 1000) {
println(i)
i += 100
}

How to do it...

  1. Declare a range of the Char type using the downTo() function:
'z' downTo 'a'
  1. Convert the range to a progression with a custom step value using the step() function:
'z' downTo 'a' step 2
  1. Use the forEach() function to iterate through the elements of the progression and print each of them to the console:
('z' downTo 'a' step 2).forEach { character -> print(character) }

How it works...

In the result, we are going to get the following code printed to the console:

zxvtrpnljhfdb

In the beginning, we declared a range containing all the alphabet characters in decreasing order with the downTo() function. Then, we transformed the range a the custom progression containing every second character with the step() function. Finally, we are using the Iterable.forEach() function to iterate through the next elements of the progression and print each of them to the console.

The step() extension function is available for the IntProgression, LongProgression, and CharProgression types. Under the hood, it creates a new instance of a progression copying the properties of the original one and setting up the new step value.

See also

  • Apart from iteration, range expressions are useful for defining flow control conditions. You can read more about this in the Using range expressions with flow control statements recipe.

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