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Modern C++: Efficient and Scalable Application Development

You're reading from   Modern C++: Efficient and Scalable Application Development Leverage the modern features of C++ to overcome difficulties in various stages of application development

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Product type Course
Published in Dec 2018
Publisher
ISBN-13 9781789951738
Length 702 pages
Edition 1st Edition
Languages
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Authors (2):
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Marius Bancila Marius Bancila
Author Profile Icon Marius Bancila
Marius Bancila
Richard Grimes Richard Grimes
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Richard Grimes
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Table of Contents (24) Chapters Close

Title Page
Copyright
About Packt
Contributors
Preface
1. Understanding Language Features FREE CHAPTER 2. Working with Memory, Arrays, and Pointers 3. Using Functions 4. Classes 5. Using the Standard Library Containers 6. Using Strings 7. Diagnostics and Debugging 8. Learning Modern Core Language Features 9. Working with Numbers and Strings 10. Exploring Functions 11. Standard Library Containers, Algorithms, and Iterators 12. Math Problems 13. Language Features 14. Strings and Regular Expressions 15. Streams and Filesystems 16. Date and Time 17. Algorithms and Data Structures 1. Other Books You May Enjoy Index

Strings and numbers


The Standard Library contains various functions and classes to convert between C++ strings and numeric values.

Converting strings to numbers

The C++ standard library contains functions with names like stod and stoi that convert a C++ string object to a numeric value (stod converts to a double and stoi converts to an integer). For example:

    double d = stod("10.5"); 
    d *= 4; 
    cout << d << "n"; // 42

This will initialize the floating-point variable d with a value of 10.5, which is then used in a calculation and the result is printed on the console. The input string may have characters that cannot be converted. If this is the case then the parsing of the string ends at that point. You can provide a pointer to a size_t variable, which will be initialized to the location of the first character that cannot be converted:

    string str = "49.5 red balloons"; 
    size_t idx = 0; 
    double d = stod(str, &idx); 
    d *= 2; 
    string rest = str.substr...
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