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Java Coding Problems

You're reading from   Java Coding Problems Become an expert Java programmer by solving over 250 brand-new, modern, real-world problems

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Product type Paperback
Published in Mar 2024
Publisher Packt
ISBN-13 9781837633944
Length 798 pages
Edition 2nd Edition
Languages
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Author (1):
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Anghel Leonard Anghel Leonard
Author Profile Icon Anghel Leonard
Anghel Leonard
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Table of Contents (16) Chapters Close

Preface 1. Text Blocks, Locales, Numbers, and Math 2. Objects, Immutability, Switch Expressions, and Pattern Matching FREE CHAPTER 3. Working with Date and Time 4. Records and Record Patterns 5. Arrays, Collections, and Data Structures 6. Java I/O: Context-Specific Deserialization Filters 7. Foreign (Function) Memory API 8. Sealed and Hidden Classes 9. Functional Style Programming – Extending APIs 10. Concurrency – Virtual Threads and Structured Concurrency 11. Concurrency ‒ Virtual Threads and Structured Concurrency: Diving Deeper 12. Garbage Collectors and Dynamic CDS Archives 13. Socket API and Simple Web Server 14. Other Books You May Enjoy
15. Index

21. Computing the quotient of the arguments and result overflow

Let’s start with two simple computations, as follows:

-4/-1 = 4, 4/-1 = -4

This is a very simple use case that works as expected. Now, let’s keep the divisor as -1, and let’s change the dividend to Integer.MIN_VALUE (-2,147,483,648):

int x = Integer.MIN_VALUE;
int quotient = x/-1; // -2,147,483,648

This time, the result is not correct. The int domain was overflowed because of |Integer.MIN_VALUE| > |Integer.MAX_VALUE|. It should be the positive 2,147,483,648, which doesn’t fit in the int domain. However, changing the x type from int to long will solve the problem:

long x = Integer.MIN_VALUE;
long quotient = x/-1; // 2,147,483,648

But the problem will reappear if, instead of Integer.MIN_VALUE, there is Long.MIN_VALUE:

long y = Long.MIN_VALUE; // -9,223,372,036,854,775,808
long quotient = y/-1;    // -9,223,372,036,854,775,808

Starting with JDK 18, the Math...

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